C# – Single Dimensional Array

Today we will explore in brief single dimensional array;

Index vs. Elements

Accessor vs. Stored Values

Indexes are zero based

Declaring Arrays

string[] myArray = new string[3];

Declaring and Initializing Arrays

string myString = myArray[3]{"John","Bob",Martin"};

Setting / Getting Values

string mystring = myArray[1] // Retrieve the second element

myArray[0] = myString;  //Stes first element

As usual, a bit detailed explanation from microsoft.com

You can declare a single-dimensional array of five integers as shown in the following example:

int[] array = new int[5];

This array contains the elements from array[0] to array[4]. The new operator is used to create the array and initialize the array elements to their default values. In this example, all the array elements are initialized to zero.

An array that stores string elements can be declared in the same way. For example:

string[] stringArray = new string[6];

Array Initialization

It is possible to initialize an array upon declaration, in which case, the rank specifier is not needed because it is already supplied by the number of elements in the initialization list. For example:

int[] array1 = new int[] { 1, 3, 5, 7, 9 };

A string array can be initialized in the same way. The following is a declaration of a string array where each array element is initialized by a name of a day:

string[] weekDays = { "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat" };

When you initialize an array upon declaration, you can use the following shortcuts:

int[] array2 = { 1, 3, 5, 7, 9 };
string[] weekDays2 = { "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat" };

It is possible to declare an array variable without initialization, but you must use the new operator when you assign an array to this variable. For example:

int[] array3;
array3 = new int[] { 1, 3, 5, 7, 9 };   // OK
//array3 = {1, 3, 5, 7, 9};   // Error

C# 3.0 introduces implicitly typed arrays. For more information, see Implicitly Typed Arrays.

Value Type and Reference Type Arrays

Consider the following array declaration:

SomeType[] array4 = new SomeType[10];

The result of this statement depends on whether SomeType is a value type or a reference type. If it is a value type, the statement creates an array of 10 elements, each of which has the type SomeType. If SomeType is a reference type, the statement creates an array of 10 elements, each of which is initialized to a null reference.

For more information about value types and reference types, see Types.


Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s

This site uses Akismet to reduce spam. Learn how your comment data is processed.

%d bloggers like this: